Heights of adult men have a mean of 69.0 inches and a standard deviation of 2.8 inches. Approximately what percentage of adult men have a height between 66.2 and 77.4 inches? Must show the number and the empirical rule

Answer 1

You have to find z scores first.
66.2-69.0 then divide by 2.8

77.4 - 69.0 then divide by 2.8

Now, you have to find the area between those two z scores. The empirical rule tells you the % between -3 and 3 standard deviations, between -2 and 2 sds and between -1 and 1 standard deviations.

Answer 2

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