The ionic compound tin(II) fluoride is composed of 1 Sn²⁺ ion and 2 F⁻ ions.
This is because "tin(II)" indicates that tin has a +2 oxidation state (Sn²⁺), and fluoride (F) has a -1 charge (F⁻). To create a neutral compound, you need two fluoride ions to balance the +2 charge from one tin ion. Therefore, the correct pair of ions in tin(II) fluoride is:
1 Sn²⁺ ion and 2 F⁻ ions.