Mercury(I) bromide is represented as \( \text{Hg}_2\text{Br}_2 \). In this compound, the mercury exists as a dimer, which means it is composed of \( \text{Hg}_2^{2+} \) ions. Therefore, mercury(I) bromide is assembled from:
- 1 \( \text{Hg}_2^{2+} \) ion and 2 \( \text{Br}^- \) ions.
Thus, the correct pair of ions in mercury(I) bromide is:
- 1 Hg2²⁺ ion and 2 Br⁻ ions.