I guess you have a rock weighing 100 grams
I guess it started out all Lokium at t = 0 ?
if it has a half life of T years
then
fraction Lokium = (1/2)^n where n is the number of half lives
here
fraction of Lolium seems to be 5/100
so
5/100 = (1/2)^n
log .05 = n log .5
n = log .05/log .5 = -1.3/ -0.301 = 4.33 half lives
so that rock is 4.33 half lives old
Now I guess you have experimental data that gives you fraction of Lokium versus time
something like'
fraction mass/original mass = f = e^-kt
find k from the data using ln f = - k t
then for half life we want to solve for T when the fraction is 1/2
1/2 = e^-kT
ln 0.5 = - k T
T = 0.693 / k where T is the half life
Having studied the data for patterns and trends, you should now be able to draw some conclusions about knowing the half-life of the element Lokium would help you determine the absolute age of rock in which this element is found. imagine you have found a rock that has 5 grams (a.k.a. cubes) of Lokium and 95 grams of DOL. Determine the absolute age of that rock. Assume that each trail in your experiment represents 1,000 years. Show all work.
2 answers
could you do the fraction Lolium be 40/100