"y varies jointly with x and z" means
y = k(xz)
when x = 4, z = 8, y = 16
16 = k(4)(8)
k = 16/32 = 1/2
y = (1/2)xz
Having problems with this question please help solve. Suppose y varies jointly with x and z. When x=4 and z=8, then y=16. Find the constant of variation and the joint variation equation.
4 answers
Thanks
1.A
2.A
3.C
4.A
5.D
6.B
7.C
8.A
9.B
10.D
11.D
12.B
13.A
14.B
15.A
16-18 are open ended, someone else can give you those answers.
2.A
3.C
4.A
5.D
6.B
7.C
8.A
9.B
10.D
11.D
12.B
13.A
14.B
15.A
16-18 are open ended, someone else can give you those answers.
y u lie @Hisoka?
1 answer