A(3,4), B(−1,1), and C(−2,5)
A to B
in x = -1 - 3 = -4
in y = 1 - 4 = -3
distance AB = sqrt (3^2+4^2 = 5
B to C
-2 + 1 = -1
5 - 1 = 4
sqrt (17) = 4.12
C to A
-5
1
sqrt 26
5.10
so 5 + 4.12 + 5.10 = 14.22
has vertices at A(3,4), B(−1,1), and C(−2,5).
Triangle A B C in the plane with the coordinates as described in the text.
What is the approximate perimeter of △ABC?
15 units
68 units
14.2 units
8.2 units
i thinks it is either 8.2 or 14.2
1 answer