H3C6H5O7(aq) + 3NaHCO3(aq)----Na3C6H5O7(aq) + 3H2O(i) + 3CO2.
NaHCO3 = 2.00g
H3C6H5O7 = 0.76
CO2 = 0.07g
1.Determine which reactant is the limiting reactant . describe your reasoning.
2. Calculate the theoretical yield of carbon dioxide in the plastic
3. what is the actual yield in this experiment.
DrBobb222
2 answers
I worked one like this yesterday. Only the numbers have changed. The process is the same. Try it. I'll help you through if you explain in detail what you don't understand.
DrBobb222
To determine which reactant is the limiting reactant
if i convert all to mols
like mols of NaHCO3 = 83.99= 84
then 2.00/84 = 0.0238
mols of H3C6H5O7 = 192.123= 192.1
then 0.76/192.1 = 0.0039
CO2 = 44
0.07/44 =0.0016
then CO2 is limiting reactant
is this correct DrBobb222
To determine which reactant is the limiting reactant
if i convert all to mols
like mols of NaHCO3 = 83.99= 84
then 2.00/84 = 0.0238
mols of H3C6H5O7 = 192.123= 192.1
then 0.76/192.1 = 0.0039
CO2 = 44
0.07/44 =0.0016
then CO2 is limiting reactant
is this correct DrBobb222