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Calculate the solubility of 43g of NaCl containing 100ml of water at temperature of 20 degrees

Consider the folllowing chemical equation TiCL4(g) + @Mg(i) --- Ti(s) + 2MgCl(i) 3.54 x 10 to powerof 7g of TiCl4(g) were reacted completely and 7.91 x 10 to pwer of 10 of Ti(s) was obtained in the experiment, A) Calculate the theoretical yield of Ti(s) b...

Sample of 10.7g of O2 reacts completely with CO to form CO2 3a) How many grams of CO2 will be formed. So 10.7g (1mol/32g) (2molCO2/2molCO2)(22.01gCO2/1molCO2) = 14.7g. Please is this right 3b) is the mass of CO2 ypu determined in the equation (3a) the min...

H3C6H5O7(aq) + 3Na3HCO3(q)---Na3C6H5O7(aq) + 3H2O(l) + #CO2(g) NaHCO3 = 1.00g H3C6H5O5 = 0.76g CO2= 0.5g 1) show that equivalence amount of cirtic acide for 1.00g of sodium bicarbonate is 0.76g 2)Calculate the theoretical yield of carbon dioxide from 1.00...

H3C6H5O7(aq) + 3NaHCO3(aq)----Na3C6H5O7(aq) + 3H2O(i) + 3CO2. NaHCO3 = 2.00g H3C6H5O7 = 0.76 CO2 = 0.07g 1.Determine which reactant is the limiting reactant . describe your reasoning. 2. Calculate the theoretical yield of carbon dioxide in the plastic 3....

Which career I able to do with this subjects

i need help Drbob222

thank you can you check 3c, found my mistake on 3a 3c please is due now @DrBob222

DrBobb222 To determine which reactant is the limiting reactant if i convert all to mols like mols of NaHCO3 = 83.99= 84 then 2.00/84 = 0.0238 mols of H3C6H5O7 = 192.123= 192.1 then 0.76/192.1 = 0.0039 CO2 = 44 0.07/44 =0.0016 then CO2 is limiting reactant...

The real answer is A: 16 B:1 C:2

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