H2S + 2NaOH -> Na2S + 2H2O

2.48g of sodium hydroxide is dissolved in water and 1.30g of hydrogen sulfide bubbled through the solution.
a) calculate the mass of NNa2S produced in solution
b) calculate the mass of the excess reagent that remains unreacted

3 answers

how many moles of HS in 1.30g? and in 2.48g NaOH?
each mole of H2S needs 2 moles of NaOH.
so, ...

2 moles

4 and 6

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