To find the mass of hydrogen gas produced, we need to determine the amount of moles of sodium hydroxide (2NaOH) produced and then use the stoichiometry of the balanced equation to find the amount of moles of hydrogen gas (H2) produced. Finally, we can convert the moles of hydrogen gas to grams using the molar mass of hydrogen.
1. Calculate the amount of moles of sodium hydroxide produced:
Mass of sodium hydroxide = 42g
Molar mass of sodium hydroxide (2NaOH) = 2(22.99 g/mol) + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol
Amount of moles of sodium hydroxide produced = mass of sodium hydroxide / molar mass of sodium hydroxide
= 42g / 39.00 g/mol
≈ 1.08 mol
2. Use the stoichiometry of the balanced equation to find the amount of moles of hydrogen gas produced:
According to the balanced equation, 2 moles of sodium (2Na) react with 2 moles of water (2H2O) to produce 2 moles of sodium hydroxide (2NaOH) and 1 mole of hydrogen gas (H2).
So, the amount of moles of hydrogen gas produced = 1.08 mol
3. Convert the amount of moles of hydrogen gas to grams using the molar mass of hydrogen:
Molar mass of hydrogen (H2) = 2(1.01 g/mol) = 2.02 g/mol
Mass of hydrogen gas produced = amount of moles of hydrogen gas * molar mass of hydrogen
= 1.08 mol * 2.02 g/mol
≈ 2.18 g
Therefore, the mass of the hydrogen gas produced (H2) is approximately 2.18 grams.
Students massed 50g of sodium (2Na) and 27g of water (2H2O). They combined the 2 reactants and produced the products.
2Na + 2H2O --> 2NaOH + H2
If 42g of sodium hydroxide (2NaOH) was produced, what is the mass of the hydrogen gas produced (H2)?
1 answer