H2OSO4+XKOH K2SO4+YH2 with the calculation and formula

Answer 1

The given balanced chemical equation is:

H2SO4 + 2KOH ⟶ K2SO4 + 2H2O

From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of KOH to form 1 mole of K2SO4 and 2 moles of H2O.

To determine the stoichiometry of the reaction, we need to know the molar ratios between the reactants and products.

Let's assume that the unknown values are represented by X and Y.
Thus, the balanced chemical equation becomes:

H2SO4 + XKOH ⟶ K2SO4 + YH2O

Since H2SO4 is a strong acid and KOH is a strong base, they will completely dissociate in water.

From the equation, we can determine the stoichiometric relationship as follows:

1 mole of H2SO4 reacts with X moles of KOH to form 1 mole of K2SO4 and Y moles of H2O.

Therefore, the balanced chemical equation with the unknown values can be written as:

H2SO4 + XKOH ⟶ K2SO4 + YH2O

To find the values of X and Y, we need additional information or data.