Calculate the theoretical yield of NaCl (using mass-to-mass calculation). (Use the mass of

Question

sodium carbonate reactant used as the starting point, along with the relevant mole ratio from the
balanced equation to perform this calculation). Work must be shown for full credit.
1 Na2CO3(s) + 2 HCl(aq) ⟶ 2 NaCl(aq) + 1 CO2(g) + 1 H2O(l)

Answer 1

I have removed the 1 coefficients. They are completely unnecessary.
Na2CO3(s) + 2 HCl(aq) ⟶ 2 NaCl(aq) + CO2(g) + H2O(l)
But how do you calculate the theoretical yield of anything without the masses of the starting materials.?

Answer 2

the mass of the sodium carbonate is 0.575g, while the mass of the sodium chloride is 0.577g

Answer 3

thank you.
Na2CO3(s) + 2 HCl(aq) ⟶ 2 NaCl(aq) + CO2(g) + H2O(l)
mass Na2CO3 = 0.575
mass NaCl obtained = 0.577
Here is a step by step procedure that will work all of these problems.
1. Write and balance the equation. You have done that.
2. Convert the initial reagent to mols. mols Na2CO3 = grams/molar mass = 0.575/106 = 0.00542
3. Using the coefficients in the balanced equation convert mols Na2CO3 to mols NaCl.
0.00542 mols Na2CO3 x (2 mols NaCl/1 mol Na2CO3) = 0.00542*2 = about 0.01 but you should use a more accurate number.
4. Convert mols NaCl to grams. g = mols x molar mass = about 0.01 x 58.5 = about 0.6. Again that's just a close estimate. This number is the theoretical yield.
5. If you wish to convert that to %yield (the problem didn't ask for that)
% yield = (actual yield of 0.577/theoretical yield of 0.6 or whatever)* 100 = ? or about 91%
Hope this helps.

Answer 4

thank you so much!