First, we need to determine the limiting reactant by using the concept of mole ratios.
The balanced equation tells us that 1 mole of CaCl2 reacts with 1 mole of Na2CO3 to produce 1 mole of CaCO3.
Let's calculate the number of moles of each reactant:
Number of moles of CaCl2 = 20g / 111g/mol = 0.18 mol
Number of moles of Na2CO3 = 20g / 106g/mol = 0.19 mol
Since we have slightly more moles of Na2CO3, it is not the limiting reactant. Therefore, CaCl2 is the limiting reactant.
We can now calculate the theoretical yield of CaCO3 by using the mole ratio:
1 mole of CaCl2 produces 1 mole of CaCO3
0.18 mol of CaCl2 produces 0.18 mol of CaCO3
The molar mass of CaCO3 is:
(40g/mol + 12g/mol + 48g/mol) = 100g/mol
The theoretical yield of CaCO3 is:
0.18 mol x 100g/mol = 18g
Therefore, the theoretical yield of CaCO3 is 18g.
20 g of calcium chloride reacts with 20 g of sodium carbonate to form calcium carbonate and sodium chloride.
CaCl2+ Na2CO3 → CaCO3 + 2NaCl
Calculate the theoretical yield of CaCO3
(Molar mass: Ca 40g/mol; O 16 g/mol; C 12 g/mol; Cl 35.5 g/mol)
1 answer
1 answer