1. Calculate the number of moles of each compound:
- Calcium chloride (CaCl2): 20 g / 110 g/mol = 0.182 moles
- Sodium carbonate (Na2CO3): 20 g / 106 g/mol = 0.189 moles
2. Determine the limiting reactant:
- To determine the limiting reactant, we need to compare the number of moles of each compound and their coefficients in the balanced equation. In this case, we have one mole of CaCl2 reacting with one mole of Na2CO3. Since the number of moles of Na2CO3 is slightly higher than that of CaCl2, it is the limiting reactant.
- Theoretical yield of CaCO3: 0.189 moles x 1 mol CaCO3/1 mol Na2CO3 x 100 g/mol = 18.9 g
3. Calculate the actual yield of CaCO3:
- We don't have information about the actual yield, so we cannot compare it with the theoretical yield.
4. Calculate the percent yield:
- % yield = (actual yield / theoretical yield) x 100%
- Since we don't have the actual yield, we cannot calculate the percent yield.
20 g of calcium chloride reacts with 20 g of sodium carbonate to form calcium carbonate and sodium chloride.
CaCl2+ Na2CO3 → CaCO3 + 2NaCl (Molar mass: Ca 40g/mol; O 16 g/mol; C 12 g/mol; Cl 35.5 g/mol)
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