H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(l)

Question

If I use 0.025 moles of NaOH to neutralize the Oxalic acid, how many moles of Oxalic acid are there?

Answer 1

0.025 mols NaOH = 1/2 * 0.025 mols H2C2O4