Gravel is being dumped from a conveyor belt at a rate of 10 ft^3/min. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. How fast is the height of the pile increasing when the pile is 23 feet high?
2 answers
Im working on same problem..... sorry no help here
volume of cone = (1/3)pi(r^2)h
but h=2r or r = h/2
then volume = (1/12)pi(h^3)
dV/dt = (1/4)pi (h^2) dh/dt
10 = (1/4)pi (23^2)dh/dt solve for dh/dt
but h=2r or r = h/2
then volume = (1/12)pi(h^3)
dV/dt = (1/4)pi (h^2) dh/dt
10 = (1/4)pi (23^2)dh/dt solve for dh/dt