To graph the first equation, y - x = 3, we can rearrange it into slope-intercept form, which is y = mx + b. In this case, m represents the slope and b represents the y-intercept.
By moving the -x term to the other side of the equation, we get y = x + 3. This tells us that the slope is 1 and the y-intercept is 3.
To graph the second equation, y = -4x - 2, it is already in slope-intercept form. The slope is -4 and the y-intercept is -2.
Now we can plot the two lines on a coordinate plane:
First equation:
y = x + 3
We know the y-intercept is 3, so we can plot a point at (0, 3). From there, we can use the slope of 1 to find other points. For example, if we go up 1 and to the right 1 from the y-intercept, we get (1, 4). We can repeat this process to find other points and connect them to create the line.
Second equation:
y = -4x - 2
The y-intercept is -2, so we can plot a point at (0, -2). From there, we can use the slope of -4 to find other points. For example, if we go down 4 and to the right 1 from the y-intercept, we get (1, -6). We can repeat this process to find other points and connect them to create the line.
Once we have both lines graphed, we can visually see where they intersect. That point is the solution to the system of equations.
Note: The graph is not provided here as it is best to plot the points and lines on an actual coordinate plane for accurate visualization.
Graph the two linear equations shown below on a coordinate plane. Ar which coordinate point do they intersect?
y - x = 3
y = -4x - 2
1 answer
1 answer