To graph the two linear equations, we first need to convert them to slope-intercept form (y = mx + b). We have:
-2x + 3y = 18
3y = 2x + 18
y = (2/3)x + 6
2x + 3y = 6
3y = -2x + 6
y = (-2/3)x + 2
Now we can plot these two equations on a coordinate plane:
The first equation (2/3)x + 6 passes through (0,6) and (-3, 4).
The second equation (-2/3)x + 2 passes through (0,2) and (3,0).
Therefore, the two equations intersect at the point (-3, 4). So, the answer is D. (-3, 4).
Graph the two linear equations shown below ok a coordinate plane. at which coordinate point do they intersect?
-2x + 3y = 18
2x + 3y = 6
A. (-1 , 2)
B. (-2, 3)
C. (3, -4)
D. (-3, 4h
F. infinite solutions
G. No solutions
1 answer