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Graph the linear equations using a table of values. y(1) =1/3x - 3 y(2) = 1/3x + 1 x y(1) 1/3x-3 y(2) 1/3x + 1 (x,y(1)) (x, y(2...Question
                Graph the linear equations using a table of values. 
y(1) =1/3x - 3
y(2) = 1/3x + 1
x y(1)
1/3x-3 y(2)
1/3x + 1 (x,y(1))
(x, y(2))
3
6
-9
            
            
        y(1) =1/3x - 3
y(2) = 1/3x + 1
x y(1)
1/3x-3 y(2)
1/3x + 1 (x,y(1))
(x, y(2))
3
6
-9
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT 3.5
            
    To graph the linear equations, we need to choose values for x and calculate the corresponding values of y(1) and y(2). 
Here is the table of values:
x | y(1) = 1/3x - 3 | y(2) = 1/3x + 1
----------------------------------------------
3 | 1 | 2
6 | 1 | 3
-9 | -6 | -2
Now, we can plot these points on a graph:
For y(1), we plot the points (3, 1), (6, 1), and (-9, -6). Then, we draw a straight line through these points.
For y(2), we plot the points (3, 2), (6, 3), and (-9, -2). Then, we draw a straight line through these points.
The graph will have two intersecting lines that represent the linear equations y(1) = 1/3x - 3 and y(2) = 1/3x + 1.
    
Here is the table of values:
x | y(1) = 1/3x - 3 | y(2) = 1/3x + 1
----------------------------------------------
3 | 1 | 2
6 | 1 | 3
-9 | -6 | -2
Now, we can plot these points on a graph:
For y(1), we plot the points (3, 1), (6, 1), and (-9, -6). Then, we draw a straight line through these points.
For y(2), we plot the points (3, 2), (6, 3), and (-9, -2). Then, we draw a straight line through these points.
The graph will have two intersecting lines that represent the linear equations y(1) = 1/3x - 3 and y(2) = 1/3x + 1.
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