graph the function. find the vertex line of symmetry, and maximum or minimum value. f(x)=(x+3)^2-4

Answer 1

F(x) = Y = (X + 3)^2 - 4.
Vertex form : Y = a(X - h)^2 + k.
V(h,k) = (-3,-4). a is positive; the
parabola opens upward. Therefore, the
the vertex is at a min. The line of
symmetry = h = -3.