Ask a New Question
Search
Graph the equation. Identify the vertices, foci, and asymptotes of the hyperbola.
Y^2/16-x^2/36=1
I think....vertices (0,4),(0,-4) foci???
asymptotes y=+/- 2x/3
Ask a New Question
or
answer this question
.
Similar Questions
1. A hyperbola has vertices (+4,0) and one focus (5,0). What is the standard-form equation of the hyperbola?
2. State the
1 answer
1. A hyperbola has vertices (±4,0) and one focus (5,0). What is the standard-form equation of the hyperbola?
2. State the
1 answer
Find an equation for the hyperbola described:
1) Vertices at (0,+/- 10); asymptotes at y= 5/3x 2) Vertices at (-+5,0); foci at
0 answers
What are the vertices, foci, and asymptotes of the hyperbola with the equation
16x^2 - 4y^2 = 64
1 answer
more similar questions