To graph the equation \(9 - x = \frac{3}{2}y\) in slope-intercept form, we first need to rearrange the equation into the format \(y = mx + b\).
Starting from the original equation: \[ 9 - x = \frac{3}{2}y \]
We can isolate \(y\) by multiplying both sides by \(\frac{2}{3}\): \[ \frac{2}{3}(9 - x) = y \]
Distributing \(\frac{2}{3}\): \[ y = \frac{2}{3}(9) - \frac{2}{3}x \] \[ y = 6 - \frac{2}{3}x \]
Now, we can rewrite this in slope-intercept form as: \[ y = -\frac{2}{3}x + 6 \]
Here, the slope \(m = -\frac{2}{3}\) and the y-intercept \(b = 6\). This means the line crosses the y-axis at 6 and has a slope indicating it decreases by \(\frac{2}{3}\) for every unit increase in \(x\).
Let's find two points to plot:
- The y-intercept: when \(x = 0\), \(y = 6\) → point \((0, 6)\)
- Another point: Let's choose \(x = 3\): \[ y = -\frac{2}{3}(3) + 6 = -2 + 6 = 4 \] → point \((3, 4)\)
Using these points \((0, 6)\) and \((3, 4)\), we can graph the line.
Based on the options presented, the second illustration, which shows a downward slanting line that passes through the plotted points \((0, 6)\) and \((3, 4)\), is the correct graph of the equation \(9 - x = \frac{3}{2}y\).