What is the equation for the line in slope-intercept form?



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Graph of a line on a coordinate plane. The horizontal x axis ranges from negative 20 to 20 in increments of 2. The vertical y axis ranges from negative 20 to 20 in increments of 2. A line passes through points begin ordered pair negative 2 comma 13 end ordered pair and begin ordered pair 0 comma 5 end ordered pair and begin ordered pair 3 comma negative 7 end ordered pair and begin ordered pair 4 comma negative 11 end ordered pair.

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The equation for the line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

To find the slope (m), we can use the formula:
m = (y2 - y1)/(x2 - x1)

Using the points (-2, 13) and (4, -11), we have:
m = (-11 - 13)/(4 - (-2))
m = (-24)/(6)
m = -4

Now we need to find the y-intercept (b). We can use the formula:
b = y - mx

Using the point (0, 5), we have:
b = 5 - (-4)(0)
b = 5

Therefore, the equation for the line is:
y = -4x + 5