well, did you not just plug in the points given?
g(1/4) = -9, so
-2a+k = -9
g(16) = -6, so
4a+k = -6
a = 1/2
k = -8
g(x) = 1/2 log_2(x) - 8
Graph of f(x)=log_2(x) has been transformed to g(x)=alog_2(x)+k. The transformed image passes through the points (1/4,-9) and (16,-6). Determine a and k.
No idea. Thanks!
1 answer
1 answer