the remaining fraction after t days is
f(t) = (1/2)^(t/2.6)
Your equation is exactly right.
After 1 day, f(1) = (1/2)^(1/2.6) = 0.766 = 76.6%
After 1 week, f(7) = (1/2)^(7/2.6) = 0.155 = 15.5%
Gold-198 with a half life of 2.6 days is used to diagnose and treat liver disease. Write a half life decay equation that relates the mass of au-198 remaining to time in days.
What percentage of a sample of Au-198 would reamin after 1 day, 1 week?
Given the information, I could only find the value off t in the equation A=Ao(1/2)^t/h
How am I supposed to solve this question?
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