Glycerine has an index of refraction of 1.47. What is the critical angle for a light ray traveling from:
a)Glycerin into air
b)Glycerin into water
a) I know- n1=1.47 n2=1 angle of refraction=90
1.47(sin.anglei)= sin90
1.47(sin.anglei)=1
sin.anglei=0.6803
angle of incidence=42.865 degrees
b) I know n1=1.47 n2=1.33 angle of refraction=90
1.47(sin.anglei)=1.33
sin.anglei=0.9048
angle of incidence=64.79 degrees
Do I have the right idea? They put it out of a lot of marks so I wondered if I was missing something...
Thanks a bunch :)
3 answers
Yes, right idea. I did not check arithmetic.
looks good
Thanks guys!!! 99% on my midterm mainly because of your help so your time is very much appreciated :) <3
0 answers