Given the reaction: 3 Cu + 8 HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

If 12.0 moles of copper react, how many grams of HNO3 are needed?

2 answers

what is 12*8/3 moles?
what is the above moles multiplied by the formula mass of Nitric acid?
you guys really need to be sure that y'all are right before y'all give give your answers. That's juts my opinion