Given the reaction

3 NO2(g) + H2O(l) �¨ 2 HNO3(l) + NO(g) ƒ¢rH = -72.0 kJ,

calculate the molar enthalpy of reaction, rH for:

1) NO2(g)
2) H20 (l)
3) HNO3 (l)
4) NO (g)

Express you answer in Kj/mol