given the quadratic equation expression x^2+10*x+12 find the turning point of its graph by using the technique known as completing the square.

Question

given the quadratic equation expression x^2+10*x+12 find the turning point of its graph by using the technique  known as completing the square.

Reiny · Answer

let y = x^2 + 10x + 12
= (x^2 + 10x + 25 - 25) + 12
= ( (x+5)^2 - 25) + 12
= (x+5)^2) - 25 + 12
= (x+5)^2 - 13

we have found the vertex to be (-5,-13), which for a parabola would be the turning point.