you can read the x-intercepts right off the original equation
once you expand it to the desired form, the y-intercept is just the value of c.
The vertex (turning point) is midway between the x-intercepts.
Since the coefficient of x^2 is positive, the parabola opens upward.
a)Express y = 2 (x - 1) (x - 5) in the form y = ax^2 + bx + c.
b) From the above quadratic equation calculate the following:
I) x and y intercepts
II) Coordinate of the turning point
III) Is the graph a maximum or minimum turning point?
1 answer