Given the linear equation y=1/3x-3, find the y-coordinates of the points (-6, ), (-3, ), and (6, )

Answer 1

Y = X/3 - 3.

Y = -6/3 - 3 = -5, (-6 , -5).

Y = -3/3 - 3 = -4, (-3 , -4).

Y = 6/3 - 3 = -1, (6 , -1).