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Given the linear equation y=2/3x+1, find the y-coordinates of the points (-6, ), (-3, ), and (3, ). Please show all of your wor...Asked by Sharday
Given the linear equation y = 4x + 2, find the y-coordinates of the points (-2, ), (1, ), and (-3, ). Please show all of your work. Plot these points and graph the linear equation.
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Answered by
Jai
to get the y-coordinates, we just substitute the value of the x-coordinates given.
at x = -2:
y = 4x + 2
y = 4(-2) + 2
y = -8 + 2
y = -6
thus (-2, -6)
at x = 1:
y = 4x + 2
y = 4(1) + 2
y = 4 + 2
y = 6
thus (1, 6)
at x = -3:
y = 4x + 2
y = 4(-3) + 2
y = -12 + 2
y = -10
thus (-3, -10)
to plot this, you locate all the points we solved above. then connect these points and extend on both ends.
hope this helps~ :)
at x = -2:
y = 4x + 2
y = 4(-2) + 2
y = -8 + 2
y = -6
thus (-2, -6)
at x = 1:
y = 4x + 2
y = 4(1) + 2
y = 4 + 2
y = 6
thus (1, 6)
at x = -3:
y = 4x + 2
y = 4(-3) + 2
y = -12 + 2
y = -10
thus (-3, -10)
to plot this, you locate all the points we solved above. then connect these points and extend on both ends.
hope this helps~ :)
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