f(0) = 0-0-3 = -3
g(0) = 0 + m = m
given: f(0) + g(0) = -5
-3 + m = -5
m = -2
then f(m) -2g(m)
= f(-2) - 2g(-2)
= 4 + 4 - 3 - 2(-3 -2)
= 8 - 3 + 10 = 15
Given the function f(x) =x^2-2x-3 and g(x)=(3/2)x +m. If f(0) + g(0) =-5, then f(m) -2g(m) is equal to:
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