Asked by Megan
Given the following vectors:
A = (28, 110°)
B = (63, -30°)
Determine A + B. Specify the sum as both Cartesian and polar.
A = (28, 110°)
B = (63, -30°)
Determine A + B. Specify the sum as both Cartesian and polar.
Answers
Answered by
bobpursley
given the angles are measured from the x axis
A=28(cos110)x+28*sin110 y
B=63*cos(-30)x+63*sin(-30)
R=A+B=
you add them, like components to like components.
Polar: R@angle
R= sqsrt(xcomponents^2 + ycomponents^2)
angle=arctan(Y/x)
A=28(cos110)x+28*sin110 y
B=63*cos(-30)x+63*sin(-30)
R=A+B=
you add them, like components to like components.
Polar: R@angle
R= sqsrt(xcomponents^2 + ycomponents^2)
angle=arctan(Y/x)
Answered by
Henry
A = 28*Cos110 + 28*sin110 = -9.58 + 26.3i.
B = 63*Cos(-30) + 63*sin(-30) = 54.6 - 31.5i.
A+B = -9.58+20.3i + 54.6-31.6i = 45.0 - 11.3i.
Cartesian = (x,y) = (45,-11.3).
Polar: Tan A = Y/X,
A = ?.
R = 45/Cos A.
Polar = (R,A degrees).
B = 63*Cos(-30) + 63*sin(-30) = 54.6 - 31.5i.
A+B = -9.58+20.3i + 54.6-31.6i = 45.0 - 11.3i.
Cartesian = (x,y) = (45,-11.3).
Polar: Tan A = Y/X,
A = ?.
R = 45/Cos A.
Polar = (R,A degrees).
Answered by
Henry
Note: A is negative and in the 4th Quadrant.
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