Given the following reaction at equilibrium, if Kc = 1.90 x 1019 at 25.0 °C, Kp = __________.
H2 (g) + Br2 (g) ↔ 2 HBr (g)
2 answers
Kp = Kc(RT)^delta n
1.90X10^19 it would remain the same
H2 (g) + Br2 (g) ↔ 2 HBr (g)
2 answers