Given the following equation:

Question

2KClO3---> 2KCl+3O2

How many moles of O2 can be produced by letting 12.00 moles of KClO3 react?

Answer 1

Here is a worked example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html

Answer 2

Molar Mass of KCLO3 (potassium chlorate)= 39.10+35.45+3(16.00)=122.55

First use what you are given, then use the mole to mole ratio to cancel out moles KClO3 and multiply keeping mol O2.
(12.00 moles KClO3)x(3 mol O2/2 mol KClO3) =18 moles O2

:D

Answer 3

if you had 12 moles, just use a simple ratio (called a molar ratio):

12 mol KClO3 * (3 mol O2)/(2 mol KClO3) = 18 mol O2 ... this is your answer!

Answer 4

How many moles of o2 can be produced by letting 12.00 moles of kclo3 decompose

Answer 5

12.00 moles of NaClO3 will produce how many grams of o2

Answer 6

so lets say i have 3.00 moles instead of 12.00 moles than does the equations still work if i can the number around?