To find \((g \circ f)(6)\), we need to evaluate \(f(6)\) first and then substitute that result into \(g(x)\).
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Calculate \(f(6)\): \[ f(x) = x - 6 \] Substitute \(x = 6\): \[ f(6) = 6 - 6 = 0 \]
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Now calculate \(g(f(6))\), which is \(g(0)\): \[ g(x) = 2x^2 - 2x + 12 \] Substitute \(x = 0\): \[ g(0) = 2(0)^2 - 2(0) + 12 = 0 - 0 + 12 = 12 \]
Therefore, the value of \((g \circ f)(6)\) is \(\boxed{12}\).