Given the curve x = √(3y^4 + 2)

i)obtain dx/dy
ii)x(dx/dy)=6y^3

My Answer:
i)6*(3y^4+2)^-1/2
ii) 6*(3y^4+2)^-1/2 *(3y^4+2)^1/2

1 answer

not quite. Remember the chain rule

dx/dy = 6y^3*(3y^4+2)^-1/2
Now you can see that (ii) is true

Doing things implicitly, it's much clearer:

x^2 = 3y^4+2
2x dx/dy = 12y^3
dx/dy = 6y^3/x
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