Asked by Jonathan
Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle or a
parallelogram. Then find the area of the quadrilateral.
E(–7, –1), F(2, –1), G(–4, –8), H(5, –8)
parallelogram. Then find the area of the quadrilateral.
E(–7, –1), F(2, –1), G(–4, –8), H(5, –8)
Answers
Answered by
Damon
draw it
the top is at -1
the bottom is at - 8
so it is 7 somethings high (question written by mathematician and they do not do units)
the top runs from -7 to +2 so is 9 somethings long
the bottom runs from -4 to +5 so is also 9 somethings long
the top starts 3 somethings to the left of the bottom
clearly it is a parallelogram
area = height * base = 7 * 9 = 63 somethings^2
the top is at -1
the bottom is at - 8
so it is 7 somethings high (question written by mathematician and they do not do units)
the top runs from -7 to +2 so is 9 somethings long
the bottom runs from -4 to +5 so is also 9 somethings long
the top starts 3 somethings to the left of the bottom
clearly it is a parallelogram
area = height * base = 7 * 9 = 63 somethings^2
Answered by
Henry
W = 2 - (-7) = 9.
L = 5 - (-4) = 9.
It is a square.
Area = 9 * 9 = 81 Square units.
L = 5 - (-4) = 9.
It is a square.
Area = 9 * 9 = 81 Square units.
Answered by
Damon - not square
left and right slope
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