you want to try that without TeX?
x^n - 1/x^n = p(x - 1/x)
...
where does z come in?
Given that $x^n - \frac1{x^n}$ is expressible as a polynomial in $x - \frac1x$ with real coefficients only if $n$ is an odd positive integer, find $P(z)$ so that $P\left(x-\frac1x\right) = x^5 - \frac1{x^5}.$
2 answers
bruh... aops problem! don't reply to this