Given that the density of the supplied vinegar solution in this experiment is

Question

1.025 g/mL, calculate the % acetic acid found in the vinegar sample.

Answer 1

Density = 1.025 g/mL; therefore, 100 mL has a mass of 1.025g/mL x 100 mL = 102.5g. 100 mL H2O should weigh 100 g; therefore, there are 2.5 g vinegar in the sample and that is 2.5%. This assumes that the volumes of vinegar and H2O are additive.