Given that Log(p+2)+Logq=r-1/3 and Log(p^2)- Logq=2r+1

Question

All in base 2.
Pls someone should help me out

Answer 1

log(p+2) + logq = r-1/3
log(p^2) - logq = 2r+1

log q(p+2) = r - 1/3
log p^2/q = 2r+1

q(p+2) = 2^(r - 1/3)
p^2/q = 2^(2r+1)

However you slice it, you have three unknowns and only two equations. What's been left out? And that pesky 1/3 is disturbing ...