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Asked by amy

I need help determining a concentration. A voltaic cell has a Hg/Hg2^2+ electrode and a Sn/Sn^2+ electrode (Enaught cell = -0.14V), Ecell = 1.04V at 298K. If [Hg2^2+]=0.24M calculate[Sn2+]. I used this formula, Ecell=Enaught Cell - (0.0592/n)logQ. my Q ends up as log(0.24M/[Sn2+]). How do I solve for the concentration of Sn2+?
18 years ago

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