given that f(x) = sqrt x/x determine the existnece of f(x) = 0 and the limits as x->0 from below and above. thus, determine the continuity of the function at x=0

1 answer

To determine the existence of f(x) = 0, we need to find the value of f(x) when x = 0.

f(0) = sqrt(0)/0 = 0/0

Since division by zero is undefined, f(0) does not exist.

Next, let's find the limits as x approaches 0 from below and above:

Limit as x approaches 0 from below:
lim x->0- sqrt(x)/x
= lim x->0- 1/sqrt(x)
= 1/0- = -∞

Limit as x approaches 0 from above:
lim x->0+ sqrt(x)/x
= lim x->0+ 1/sqrt(x)
= 1/0+ = +∞

Since the limit as x approaches 0 from below and above do not equal each other or exist, the function is not continuous at x=0.
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