Question

Rotate the region enclosed by the given functions around the x-axis. Determine the volume.
y=sqrt(sinx) ; y=0 ; x=0 ;x=pi

limits are 0 to pi
vol = π∫y^2 dx from x=0 to π
= π∫sinx dx from 0 to π
= π [-cosx] from 0 to π
= π (-cosπ - (-cos0) )
= π (1 + 1)
= 2π

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