given that cos0 = √2/2 of a triangle on the unit circle what is the sine ratio of the same triangle?

Answer 1

To find the sine ratio of the same triangle, we can use the Pythagorean identity:

sin^2(x) + cos^2(x) = 1

Since cos(0) = √2/2, we can substitute it into the equation:

sin^2(0) + (√2/2)^2 = 1

sin^2(0) + 2/4 = 1

sin^2(0) + 1/2 = 1

sin^2(0) = 1 - 1/2

sin^2(0) = 1/2

Taking the square root of both sides, we get:

sin(0) = √(1/2)

Therefore, the sine ratio of the same triangle is √(1/2).