To find h(-6), we substitute x = -6 into the expression for h(x):
h(-6) = -3(-6) + 2
h(-6) = 18 + 2
h(-6) = 20
Now, to find h(-6), we multiply -6 by the value we found for h(-6):
6 * 20 = 120
Therefore, h(of, minus, 6h(-6)) = 120.
Given h, of, x, equals, minus, 3, x, plus, 2h(x)=−3x+2, find h, of, minus, 6h(−6)
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