To find the expression \( 2B - 3C \) in standard form, let's first substitute the given expressions for \( B \) and \( C \).
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The expression for \( B \) is given as: \[ B = 3n - 10 \]
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The expression for \( C \) is given as: \[ C = n^2 - 6n - 6 \]
Now, we can substitute these expressions into \( 2B - 3C \):
First, we calculate \( 2B \): \[ 2B = 2(3n - 10) = 6n - 20 \]
Next, we calculate \( 3C \): \[ 3C = 3(n^2 - 6n - 6) = 3n^2 - 18n - 18 \]
Now, we can substitute \( 2B \) and \( 3C \) into the expression \( 2B - 3C \): \[ 2B - 3C = (6n - 20) - (3n^2 - 18n - 18) \]
Distributing the negative sign for \( -3C \): \[ 2B - 3C = 6n - 20 - 3n^2 + 18n + 18 \]
Now, combine like terms: \[ = -3n^2 + (6n + 18n) + (-20 + 18) \] \[ = -3n^2 + 24n - 2 \]
Thus, the expression \( 2B - 3C \) in standard form is: \[ \boxed{-3n^2 + 24n - 2} \]