If B, equals, 3, n, minus, 10B=3n−10 and C, equals, n, squared, minus, 6, n, minus, 6, commaC=n

2
−6n−6, find an expression that equals 2, B, minus, 3, C2B−3C in standard form.

1 answer

To find the expression \( 2B - 3C \) in standard form, let's first substitute the given expressions for \( B \) and \( C \).

  1. The expression for \( B \) is given as: \[ B = 3n - 10 \]

  2. The expression for \( C \) is given as: \[ C = n^2 - 6n - 6 \]

Now, we can substitute these expressions into \( 2B - 3C \):

First, we calculate \( 2B \): \[ 2B = 2(3n - 10) = 6n - 20 \]

Next, we calculate \( 3C \): \[ 3C = 3(n^2 - 6n - 6) = 3n^2 - 18n - 18 \]

Now, we can substitute \( 2B \) and \( 3C \) into the expression \( 2B - 3C \): \[ 2B - 3C = (6n - 20) - (3n^2 - 18n - 18) \]

Distributing the negative sign for \( -3C \): \[ 2B - 3C = 6n - 20 - 3n^2 + 18n + 18 \]

Now, combine like terms: \[ = -3n^2 + (6n + 18n) + (-20 + 18) \] \[ = -3n^2 + 24n - 2 \]

Thus, the expression \( 2B - 3C \) in standard form is: \[ \boxed{-3n^2 + 24n - 2} \]