To find g(3), we substitute x = 3 into the function g(x) = -5x + 1:
g(3) = -5(3) + 1
g(3) = -15 + 1
g(3) = -14
Therefore, g(3) = -14.
Now, to find g of g(3), we substitute the value of g(3) back into the function g(x):
g(g(3)) = g(-14) = -5(-14) + 1
g(g(3)) = 70 + 1
g(g(3)) = 71
Therefore, g(g(3)) = 71.
Given g, of, x, equals, minus, 5, x, plus, 1g(x)=−5x+1, find g, of, 3g(3).
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