y '' = 4x+3
y' = 2x^2 + 3x + C
when x = -3, y' = 2
2 = 18 - 9 + C
C = -7
so y' = 2x^2 + 3x - 7
then y = (2/3)x^3 + (3/2)x^2 - 7x + K
when x = -3, y = 1
take it from there by solving for K
Given f''(x) = 4x - 3
and f'( -3) =2 and f( -3)=-1.
Find f'(x) =______
and find f( 1) =_____
2 answers
I don't know why but the answer is wrong.